TomTieDom, [Confused]

found something else what surprised me:

code:
$a='cdbl(8)/(cdbl(3)-cdbl(8)/cdbl(3))'
$rc=Execute("$$b=$a")
? 'Result $$b = '$b
? 'Result 24=$$b = '+(24=$b)
? 'Result $$b=24 = '+($b=24)
? 'Result type = '+VarTypeName($b)

comes up with
code:
Result $b    = 24
Result 24=$b = 1
Result $b=24 = 0
Result type = Double

[Confused] [Confused]

Does anyone have an explaination for this behaviour???
_________________________
Greetz,
Patrick Rutten

- We'll either find a way or make one...
- Knowledge is power; knowing how to find it is more powerful...
- Problems don't exist; they are challenges...