Aha! But of course a bare number is... an integer.

So, $x=25 will result in $x being an integer, because the type of the expression "25" is an integer type.

$x=25.0 will result in $x being a double, because the expression "25.0" is a double type.

In the code
code:
$a=25
$b=2
$c=$a/$b
Will result in "12", because the variables $a and $b are both integer, so the math expression is integer.
The code
code:
$a=25.0
$b=2.0
$c=$a/$b
Will result in "12.5" because $a and $b are both doubles, and the result of the math expression is a double.

Nice try, but no cigar [Wink]

[ 13 June 2002, 12:58: Message edited by: Richard Howarth ]