Return from Shawns request... $Name[$PU,0]
Quote:


VarType=String
Value=Nancy


I added this one
Quote:


VarType for $a=String
Value=Cheryl


ERROR : Error in expression: this type of array not supported in expressions.!

The last ? Value = was placed just before the line
If $a <> "your choice"

And this is with putting in the suggested
$text = @CRLF + $Name[$PU,0] +" please share with " + $a + @CRLF
$LabelG.text = $text

I still believe the real issue is the line before the reported error.. this one
If $b[2] = 1 Or $ExVar < 4

To that end I got these returns
Quote:



1=Value of $B[2]
String= Type of Var for $B[2]
1=Value of $ExVar
Long=Type of Var for $ExVar
_________________________
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