Lonkero is right

IP 192.010.128.055
SubnetMask 255.255.255.000

Network ID Should be:

NetworkID 192.010.128.000

Easy conversion into binary.

3rd Otect on Subnet Mask
128,64,32,16,8,4,2,1
1,1,1,1,1,1,1,1

Network ID
1,0,0,0,0,0,0,0 = 128

Now say the 4th Octec of the Subnet Mask was 128

1 ,0 ,0 ,0 ,0,0,0,0

Network ID would be.
0 ,1 ,1 ,1 ,1,1,1,1 = 127

You should start SuperNetting the Network Address, and that would make it fun. [Big Grin]

Rich

[ 24. May 2003, 23:00: Message edited by: Richard Farthing ]